Optimizing Anagram Grouping With Hashmap
Grouping Anagrams using Sorting takes O(nlogn * m) time complexity, but can be optimized to O(n * m) with Hashmap by counting character frequencies.
Using Sorting /** * @param {string[]} strs * @return {string[][]} */ var groupAnagrams = function (strs) { let res = new Map() for (let s of strs) { const key = s.split('').sort().join('') if (!res.has(key)) { res.set(key, []); } res.get(key).push(s); } return Array.from(res.values()); }; Using Sorting takes O(nlogn * m) time complexity We can optimize to O(n * m) with Hashmap Using HashMap /** * @param {string[]} strs * @return {string[][]} */ var groupAnagrams = function (strs) { let res = new...