Extra Characters In String: Min Extra Char Left Over
Break string s into non-overlapping substrings from dictionary. Min extra chars = dp[len(s)]. DP[i] = min(dp[i-1]+1, min(dp[j]) if s[j:i] in dict).
2707. Extra Characters in a String Difficulty: Medium Topics: Array, Hash Table, String, Dynamic Programming, Trie You are given a 0-indexed string s and a dictionary of words dictionary. You have to break s into one or more non-overlapping substrings such that each substring is present in dictionary. There may be some extra characters in s which are not present in any of the substrings. Return the minimum number of extra characters left over if you break up s optimally. Example 1: Input: s = "leetscode", dictionary = ["leet","code","leetcode"] Output: 1 Explanation: We can break s in two sub...